A bullet of mass M = 1 kg, moving with a horizontal velocity of 8 m/s, hits and sticks to a block B of mass 4M= 4 kg which is initially at rest.Find the speed of the 4M block after collision.

A bullet of mass M = 1 kg, moving with a horizontal velocity of 8 m/s,

1.	A bullet of mass M = 1 kg, moving with a horizontal velocity of 8 m/s, hits and sticks to a block B of mass 4M= 4 kg which is initially at rest.Find the speed of the 4M block after collision.
Answer» <html><body><p><strong>Answer:</strong></p><p>1.6 m/s</p><p><strong>Explanation:</strong></p><p><u>Given</u><strong>:</strong></p><p>Mass of the bullet = 1 kg</p><p>Velocity of the bullet = 8 m/s</p><p>Mass of the <a href="https://interviewquestions.tuteehub.com/tag/block-18865" style="font-weight:bold;" target="_blank" title="Click to know more about BLOCK">BLOCK</a> = <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> kg</p><p><u>To <a href="https://interviewquestions.tuteehub.com/tag/find-11616" style="font-weight:bold;" target="_blank" title="Click to know more about FIND">FIND</a></u>:</p><p>Speed of the <a href="https://interviewquestions.tuteehub.com/tag/combined-409631" style="font-weight:bold;" target="_blank" title="Click to know more about COMBINED">COMBINED</a> block and bullet after collision</p><p><u>Method to find</u>:</p><p>First, we need to find out the total momentum of the carriages before the collision.</p><p><em><strong>p = m * v</strong></em><strong> </strong>(Momentum = Mass * Velocity)</p><p><em>Momentum of the bullet</em>:</p><p>p = 1 * 8</p><p>⇒ p = 8 kg m/s</p><p><em>Momentum of Block B</em>:</p><p>p = 4 * 0 (Since it was at rest)</p><p>p = 0 kg m/s</p><p><em>Total momentum of the bullet and the block</em>:</p><p>8 + 0 = <u>8 kg m/s</u></p><p>By applying the <em><strong><a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of conservation of momentum</strong></em>, we can state that the sum of momentum of the 2 bodies before collision will be equal to the sum of momentum of the 2 bodies after the collision.</p><p>Now, we need to find the <em>total mass of the bodies after the collision</em>:</p><p>4 + 1 = <u>5 kg</u></p><p>Since they are 2 non-elastic bodies, their final velocity will be the same.</p><p>To find the final velocity,</p><p>p = m * v</p><p>⇒ 8 = 5 * v</p><p>⇒ v = 8/5 = 1.6 m/s</p><p>Hence, the speed of the 4M block after collision will be <u>1.6 m/s.</u></p><p></p><p></p><p></p><p></p></body></html>

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A bullet of mass M = 1 kg, moving with a horizontal velocity of 8 m/s, hits and sticks to a block B of mass 4M= 4 kg which is initially at rest.Find the speed of the 4M block after collision.

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