A capacitor of `20 muF` is charged to `500` volts and connected in parallel ith another capacitor of `10 muF` and charged to `200` volts. The common potential isA. 400 VB. 200 VC. 100 VD. 50 V

A capacitor of `20 muF` is charged to `500` volts and connected in par

1.	A capacitor of `20 muF` is charged to `500` volts and connected in parallel ith another capacitor of `10 muF` and charged to `200` volts. The common potential isA. 400 VB. 200 VC. 100 VD. 50 V
Answer» Correct Answer - A Suppose `C_(1) and C_(2)` are capacities of two condensers charged to potentials `V_(1) and V_(2)`. Respectively. Total charge before sharing `=C_(1)V_(1)+C_(2)V_(2)` If V is the common poetnial on sharing charges, then total charge after sharing `=C_(1)V+C_(2)V=(C_(1)+C_(2))V` As mo charge is lost in the process of sharing, therefore `(C_(1)+C_(2))V=C_(1)V_(1)+C_(1)V_(1)+C_(2)V_(2)` `therefore" "V=(C_(1)V_(1)+C_(2)V_(2))/(C_(1)+C_(2))` `=((20xx10^(-6)xx500)+(10xx10^(-6)xx200))/((20xx10^(-6))+(10xx10^(-6)))` = 400 V

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A capacitor of `20 muF` is charged to `500` volts and connected in parallel ith another capacitor of `10 muF` and charged to `200` volts. The common potential isA. 400 VB. 200 VC. 100 VD. 50 V

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