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A capacitor of capacitance C is charged to a potential difference V from a cell and then disconnected from it. A charge +Q is now given to its positive plate. The potential difference across the capacitor is nowA. VB. `V + (Q)/( C)`C. `V + (Q)/(2 C)`D. `V -(Q)/( C)`, if `V lt CV` |
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Answer» Correct Answer - C `E=(sigma)/(in_(0))=((Q)/(2)+CV)/(A in_(0)),V=Ed=((Q)/(2)+CV)/((A in_(0))/(d))` `= ((Q)/(2)+CV)/(C)=V+(Q)/(2C)`. |
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