InterviewSolution
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InterviewSolution
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A car is moving with uniform acceleration along a straight line between two stops X and Y. Its speed at X and Y are `2 ms^-1 and 14 ms^-1` , ThenA. its speed at mid-point of XY is `10 ms^-1`B. its speed at a point A such that `XA : AY = 1 :3` is `5 ms^-1`C. the time to go from X to the mid-point of XY is double of that to go from mid-point to YD. the distance travelled in first half of the total time is half of the distance travelled in the second half of the time |
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Answer» Correct Answer - A::C `(14)^2=(2)^2+2 as` `:. 2as=192` units At mid point, `v^2=(2)^2+2a(s/2)` `=4+192/2=100` `:. v=10 m//s` `XA:AY=1:3` `:. XA=1/4s` and `AY=3/4s` `v_1^2=(2)^2+2a(s/4)` `=4+192/4=52` `:. v_1=sqrt52!=5 m//s` `10=2+a t_1 (v=u+at)` `:. t_1=8/a 14=10+a t_2` `:. t_2=4/a` or `t_1=2t_2` `S_1=(2t)+1/2a(t^2)`=distance travelled in first half `S_2=2(2t)+1/2a(2t)^2` `S_3=S_2-S_1`=distance travelled in second half We can see that, `S_1!=(S_3)/2` |
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