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A car moving along a straight highway with a speed of `72 km h^(-1)` is brought to a stop within the distance of `100 m`. What is the retardation of the car and how long does it take for the car to stop ? |
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Answer» Here, `u=72km h^(-1) =72 xx 5/(18)` `=20 ms^(-1)`: `v=0, S=100 m: a=? Acceleration, `a(v^(2)-u^(2))/(2 S) =(0-20^(2))/(2xx 100) =- 2 ms^(2)` i.e. retardation `=- a=2 ms^(-2)` ltbtgt Time `t= (v-u)/a = (0-20)/(-2) =10 s`. |
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