A car starts from rest and moves with uniform acceleration 'a'. At the same instant from the same point a bike crosses with a uniform velocity 'u'. When and where will they meet? What is the velocity of car with respect to the bike at the time of meeting?

A car starts from rest and moves with uniform acceleration 'a'. At the

1.	A car starts from rest and moves with uniform acceleration 'a'. At the same instant from the same point a bike crosses with a uniform velocity 'u'. When and where will they meet? What is the velocity of car with respect to the bike at the time of meeting?
Answer» Solution :Let the car and bike will meet after coving a DISTANCE S in a time .t. SEC. For car `S=(1)/(2)at^(2)……(1)` for bike `s=UT……(2)` Since they cover same distance `ut=(1)/(2)at^(2)impliest=(2u)/(a)` The car and bike will meet after a time of `(2u)/(a)` sec. The VELOCITY of car after .t. sec is `V_(car)=at=a((2u)/(a))=2u` The velocity of car w.r.t bike is `V_(rel)=2u-u=u`.