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A carbon compound contains 12.8% Carbon, 2.1% Hydrogen, 85.1% Bromine. The molecular weight of the compound is 187.9. Calculate the molecular formula.

Answer» <html><body><p></p>Solution :Step <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>: Percentage composition of the <a href="https://interviewquestions.tuteehub.com/tag/elements-969381" style="font-weight:bold;" target="_blank" title="Click to know more about ELEMENTS">ELEMENTS</a> present in the <a href="https://interviewquestions.tuteehub.com/tag/compound-926863" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUND">COMPOUND</a>. <br/> `{:(C,H,Br),(12.8,2.1,85.1):}` <br/> Step 2: Dividing with the respective atomic <a href="https://interviewquestions.tuteehub.com/tag/weights-1451449" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHTS">WEIGHTS</a> of the elements. <br/> `{:((12.8)/(12),(2.1)/(1),(85.1)/(80)),(1.067,2.1,1.067):}` <br/> Step 3: Dividing by the smallest number to get simple atomic <a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a>. <br/> `{:((1.067)/(1.067),(2.1)/(1.067),(1.067)/(1.067)),(1,2,1):}` <br/> The empirical formula is `CH_(2)Br` <br/> Empricial formula weight `12 + (2 xx 1) + 80 = 94` <br/> The molecular weight = 187.9 (given) <br/> `therefore n=(187.9)/(94)=2` <br/> `"The molecular formula" = "(empirical formula)"_(2)` <br/> `(CH_(2)Br)_(2)=C_(2)H_(4)Br_(2)`</body></html>


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