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A Carnot engine takes 3000 kcal of heat from a reservoir at 627^(@)C. The sink is at 27^(@)C. What is the amount of work done by the engine?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Temperature of the reservoir, <br/> `T_(1) = (627 + 273)<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> = 900K` <br/> Temperature of the sink, <br/> `T_(2) = (27_273)K = 300K` <br/> `:. "<a href="https://interviewquestions.tuteehub.com/tag/efficiency-20674" style="font-weight:bold;" target="_blank" title="Click to know more about EFFICIENCY">EFFICIENCY</a>", eta = 1 -(T_2)/(T_1) = 1 - (300)/(900) = 2/<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>` <br/> Again, `eta = W/(Q_1)` <br/> or, `W = etaQ_(1) = 2/3 xx 3000` <br/> `=2000 kcal = 2000 xx 4.2 xx 10^(3)<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`<br/> `=8.4 xx 10^(6) J`.</body></html>


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