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A Carnot's engine extract 1.5 xx 10^(3) kilocalorie of heat from a reservoir at 627^(@)C and exhaust it to a sink maintained at 27^(@)C. How much work is performed by the engine ? |
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Answer» Solution :Efficiency of CARNOT engine `eta = 1-(T_(2))/(T_(1))` `:.` WORK performed by engine `= (1-(T_(2))/(T_(1)))Q` `:. W = (1-(300)/(900)) xx (1.5 xx 10^(3) xx 10^(3))CAL` or `W = (2)/(3) xx 1.5 xx 10^(6) xx 4.2 J = 4.2 = 4.2 xx 10^(6) J` `:. W = 4.2 xx 10^(6) J`. |
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