A carof mass 1500 kg is moving with a speed of 12.5 ms^(-1) on a circular path of radius 20 mon a level raod what should be the frictional force between the car and the raod so that the car does not slip what should be thevalueof the coefficent of friction to attain this force

A carof mass 1500 kg is moving with a speed of 12.5 ms^(-1) on a circu

1.	A carof mass 1500 kg is moving with a speed of 12.5 ms^(-1) on a circular path of radius 20 mon a level raod what should be the frictional force between the car and the raod so that the car does not slip what should be thevalueof the coefficent of friction to attain this force
Answer» <html><body><p></p>Solution :Given `m= 15000 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a>` <br/> `v=12.5 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1)` <br/> `r=25 m` <br/> Frictionforce = Requiredcentripetalforce <br/> or`f= (mv^(2))/(r ) = (15000 xx 12.5 xx 12.5)/(20)` <br/> `=1.172 xx 10^(4) N` <br/> But `f= muR =<a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a> <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>` <br/> coefficientof friction<br/> `mu = (f )/(mg ) =- (1.172 xx 10^(4))/( 1500 xx 9.8 ) = 0.8`</body></html>