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A cell is constructed using Cu^(2+)//Cu and I^(3+)//AIelectrode what is the net cell reaction

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :From we know that `E^(@)` of `AI^(3+)//AI(-1.66 V)` is <a href="https://interviewquestions.tuteehub.com/tag/lower-1080637" style="font-weight:bold;" target="_blank" title="Click to know more about LOWER">LOWER</a> than that of `Cu^(2+)//Cu(+0.34 V)` <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> oxidation occurs at the `AI^(3+)//AI` electrode and reducation occurs at the `Cu^(2+) //Cu` electrode consequently the net cell reactin is <br/> `2 AI(s)+3 Cu^(2+)(aq)<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> 2 AI^(3+)(aq)+3Cu(s)`</body></html>


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