1.

A cell is constructed using Cu^(2+)//Cu and I^(3+)//AIelectrode what is the net cell reaction

Answer»

SOLUTION :From we know that `E^(@)` of `AI^(3+)//AI(-1.66 V)` is LOWER than that of `Cu^(2+)//Cu(+0.34 V)` THEREFORE oxidation occurs at the `AI^(3+)//AI` electrode and reducation occurs at the `Cu^(2+) //Cu` electrode consequently the net cell reactin is
`2 AI(s)+3 Cu^(2+)(aq)RARR 2 AI^(3+)(aq)+3Cu(s)`


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