InterviewSolution
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InterviewSolution
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A cell is prepared by dipping a copper rod in `1 MCuSO_(4)` solution and a nickel rod in `1M NiSO_(4)`. The standard reduction potentials of copper and nickel electrodes are `+0.34 V` and `-0.25 V` respectively. (i) Which electrode will work as anode and which as cathode? (ii) What will be the cell reaction? (iii) How is the cell represented ? (iv) Calculate the `EMF` of the cell. |
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Answer» (i) The nickel electrode with smaller `E^(@)` value `(-0.25V)` will work as anode while copper electrode with more `E^(@)` value `(+0.34V)` will work as cathode. (ii) The cell reaction may be written as: `{:("A anode", :, Ni(s) rarr Ni^(2+)(aq).+2e^(-)),("At cathode",:, Cu^(2+) (aq) +2e^(-) rarr Cu(s)),("Cell reaction",:, Ni(s) +Cu^(2+) (aq) rarr Ni^(2+)(aq) +Cu(s)):}` The cell may be represented as: `Ni(s)//Ni^(2+) (aq) || Cu^(2+)(aq)//Cu(s)` (iv) `CMF` of cell `=E_("cathode") -E_("anode")^(@) =(+0.34) -(0.25) = 0.59V` |
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