A certain gas is expanded from (1L, 10atm) to (4L, 5atm) against a constant external pressure of 1 atm. If the initial temperature of gas is 300K and heat capacity for the process is 50J ""^(@)C^(-1) (use 1L atm = 100J), then

A certain gas is expanded from (1L, 10atm) to (4L, 5atm) against a con

1.	A certain gas is expanded from (1L, 10atm) to (4L, 5atm) against a constant external pressure of 1 atm. If the initial temperature of gas is 300K and heat capacity for the process is 50J ""^(@)C^(-1) (use 1L atm = 100J), then
Answer» <html><body><p>`\|W\| = 0.3kJ`<br/>`\|<a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a>\| = 15 <a href="https://interviewquestions.tuteehub.com/tag/kj-1063034" style="font-weight:bold;" target="_blank" title="Click to know more about KJ">KJ</a>`<br/>`Delta U = 14.7 kJ`<br/>`Delta H = 15.7 kJ`</p>Solution :Constant, P, `W = - P_("ext") Delta V` <br/> `= -1 xx (<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>-1) = - 3` latern, `\|W\| = 0.3 KJ` <br/> `(P_(1)V_(1))/(T_(1)) =(P_(2)V_(2))/(T_(2)), (1 xx 10)/(<a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a>)= (4 xx 5)/(T_(2)) , T_(2) = 600K` <br/> `\|q\| = C Delta T = (50 xx 300)/(1000) = 15KJ` <br/> `Delta U = q + W = + 15 - 0.3 = 14.7` <br/> `Delta H = Delta U + Delta (PV)` <br/> `=14.7 + (5 xx 4 - 10 xx 1) xx 0.1 KJ = 15.7 KJ`</body></html>