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A certain gas occupies 0.418 litres at 27^@C and 740 mm Hg. What is the volume at S.T.P. ? |
Answer» <html><body><p><br/></p>Solution :According to the gas equation <br/> `(Р_1 V_1)/T_1 =(P_2 V_2)/T_2` <br/>In the present case, <br/> `P_1 = <a href="https://interviewquestions.tuteehub.com/tag/740-334871" style="font-weight:bold;" target="_blank" title="Click to know more about 740">740</a> " mm Hg,"V_1 = 0.418 <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>` <br/> `T_1 = 27 + 273 = <a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a> <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>` <br/>`P_2 = <a href="https://interviewquestions.tuteehub.com/tag/760-335611" style="font-weight:bold;" target="_blank" title="Click to know more about 760">760</a> " mm Hg, " V_2 = ? "" T_2 = 273 K` (at S.T.P.) <br/> Substituting the values, we have <br/> `(740 xx 0.418)/300 =(760 xx V_2)/300`<br/> `:. "" V_2 = 0.37 L`</body></html> | |