1.

A certain gas occupies 0.418 litres at 27^@C and 740 mm Hg. What is the volume at S.T.P. ?

Answer»


Solution :According to the gas equation
`(Р_1 V_1)/T_1 =(P_2 V_2)/T_2`
In the present case,
`P_1 = 740 " mm Hg,"V_1 = 0.418 L`
`T_1 = 27 + 273 = 300 K`
`P_2 = 760 " mm Hg, " V_2 = ? "" T_2 = 273 K` (at S.T.P.)
Substituting the values, we have
`(740 xx 0.418)/300 =(760 xx V_2)/300`
`:. "" V_2 = 0.37 L`


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