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A certain gas occupies 0.418 litres at 27^@C and 740 mm Hg. What is the volume at S.T.P. ? |
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Answer» `(Р_1 V_1)/T_1 =(P_2 V_2)/T_2` In the present case, `P_1 = 740 " mm Hg,"V_1 = 0.418 L` `T_1 = 27 + 273 = 300 K` `P_2 = 760 " mm Hg, " V_2 = ? "" T_2 = 273 K` (at S.T.P.) Substituting the values, we have `(740 xx 0.418)/300 =(760 xx V_2)/300` `:. "" V_2 = 0.37 L` |
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