1.

A certain gas occupies 0.418 litres at 27^@C and 740 mm of Hg. If we increase the weight of the gas to 7.5 g in the same vessel and the temperature is changed to 280 K, what would be its pressure ?

Answer»


Solution :According to the gas equation
`PV = NRT`
Now, `n= (7.5)/(181.5),R = 0.0821L " atm " K^(-1)MOL^(-1)`
`T = 280 K and V = 0.418L`
`:. "" P =(7.5/181.5xx0.0821xx280)/0.418=2.27` atm
HENCE, the pressure of the gas WOULD be 2.27 atm.


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