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A certain gas occupies 0.418 litres at 27^@C and 740 mm of Hg. If we increase the weight of the gas to 7.5 g in the same vessel and the temperature is changed to 280 K, what would be its pressure ? |
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Answer» `PV = NRT` Now, `n= (7.5)/(181.5),R = 0.0821L " atm " K^(-1)MOL^(-1)` `T = 280 K and V = 0.418L` `:. "" P =(7.5/181.5xx0.0821xx280)/0.418=2.27` atm HENCE, the pressure of the gas WOULD be 2.27 atm. |
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