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A certain gas occupies 0.418 litres at 27^@C and 740 mm of Hg. If we increase the weight of the gas to 7.5 g in the same vessel and the temperature is changed to 280 K, what would be its pressure ?

Answer» <html><body><p><br/></p>Solution :According to the gas equation <br/> `PV = <a href="https://interviewquestions.tuteehub.com/tag/nrt-1109890" style="font-weight:bold;" target="_blank" title="Click to know more about NRT">NRT</a>` <br/> Now, `n= (7.5)/(181.5),R = 0.0821L " atm " K^(-1)<a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>^(-1)` <br/>`T = <a href="https://interviewquestions.tuteehub.com/tag/280-299547" style="font-weight:bold;" target="_blank" title="Click to know more about 280">280</a> K and V = 0.418L` <br/> `:. "" P =(7.5/181.5xx0.0821xx280)/0.418=2.27` atm<br/> <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, the pressure of the gas <a href="https://interviewquestions.tuteehub.com/tag/would-3285927" style="font-weight:bold;" target="_blank" title="Click to know more about WOULD">WOULD</a> be 2.27 atm.</body></html>


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