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A certain number of spherical drops of a liquid of a liquid of radius r coalesce to form a single drop of radius R and volume V. if T is the surface tension of the liquid, then

Answer» <html><body><p>`"<a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a>"=4VT(1/<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>-1/R)"is released"`<br/>`"energy"=3VT(1/r+1/R)"is absorbed"`<br/>`"energy"=3VT(1/r-1/R)"is released"`<br/>energy is <a href="https://interviewquestions.tuteehub.com/tag/neither-1113494" style="font-weight:bold;" target="_blank" title="Click to know more about NEITHER">NEITHER</a> released nor absorbed.</p>Solution :`A_f=4piR^2=3/34pi(R^3)/( R)=(3V)/(R )` <br/> `A_i=nxx4pir^2=(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>)/(4/3 <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> r^3)4pir^2=(3V)/( r)` <br/> Hence, energy released `=(A_i-A_f)T=3VT(1/r-1/R)`</body></html>


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