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A certain particle carries -2.5 xx 10^(-16)C of static charge. Calculate the number of electrons present in it. |
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Answer» Solution :`"No.of ELECTRONS "= ("STATIC charge E")/("coulomb charge of each "e^(-))=(2.5xx10^(-16)"coulomb ")/(1.602xx10^(-19)"coulomb")` `=1.56xx10^(3)" electrons "= "1,560 electrons"`. |
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