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A certain public water supply contained 0.10 parts per billion of chloroform CHCl_(3) How many molecules of CHCl_(3)would be contained in a 0.05 ml drop of this water ? |
Answer» <html><body><p></p>Solution :Volume = 0.05 mL <br/> Amount of `CHCl_(3)` in th drop `=(0.05 xx 0.1)/<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) = 5.0 xx 10^(-12)`g <br/> Molecule <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of `CHCl_(3) = 12+1 + 3 xx 35.5` <br/> `=119.5 g mol^(-1)` <br/> Moles of `CHCl_(3)` <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> `=(5.0 xx 10^(-12))/119.5` <br/> <a href="https://interviewquestions.tuteehub.com/tag/molecules-563030" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULES">MOLECULES</a> of `CHCl_(3)` present in the drop <br/> `=(5.0 xx 10^(-12))/119.5 xx 6.022 xx 10^(23) = 2.5 xx 10^(19)`.</body></html> | |