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A certain quantity of a gas measured 500 mL at a temperature of 15^@C and 750 mm Hg What pressure is required to compress this quantity of gas into a 400 mL vessel at a temperature of 50^@C ? |
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Answer» SOLUTION :In the present case, `P_1 = 750 mm Hg`, `V_1 = 500 mL`, `T_1 = 273 + 15 = 288 K " and"P_2` = ? `V_2 = 400 ml`, `T_2 = 273 + 50 = 323 K` Therefore, ACCORDING to the gas equation, we have `(P_1 V_1)/(T_1) = (P_2 V_2)/(t_2) " or "(750 xx 500)/288=(P_2 xx 400)/323" or "P_2 = 1051 mm` Hence, the given gas should be compressed to 1051 mm pressure. |
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