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A certain quantity of a gas measured 500 mL at a temperature of 15^@C and 750 mm Hg What pressure is required to compress this quantity of gas into a 400 mL vessel at a temperature of 50^@C ? |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In the present case, <br/> `P_1 = 750 mm Hg`, <br/> `V_1 = <a href="https://interviewquestions.tuteehub.com/tag/500-323288" style="font-weight:bold;" target="_blank" title="Click to know more about 500">500</a> mL`, <br/> `T_1 = 273 + 15 = <a href="https://interviewquestions.tuteehub.com/tag/288-1834218" style="font-weight:bold;" target="_blank" title="Click to know more about 288">288</a> K " and"P_2` = ? <br/> `V_2 = 400 ml`, <br/>`T_2 = 273 + 50 = 323 K` <br/> Therefore, <a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to the gas equation, we have <br/> `(P_1 V_1)/(T_1) = (P_2 V_2)/(t_2) " or "(750 xx 500)/288=(P_2 xx 400)/323" or "P_2 = 1051 mm` <br/>Hence, the given gas should be compressed to 1051 mm pressure.</body></html> | |