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A certain quantity of a gas measured 500 mL at a temperature of 15^@C and 750 mm Hg What pressure is required to compress this quantity of gas into a 400 mL vessel at a temperature of 50^@C ?

Answer»

SOLUTION :In the present case,
`P_1 = 750 mm Hg`,
`V_1 = 500 mL`,
`T_1 = 273 + 15 = 288 K " and"P_2` = ?
`V_2 = 400 ml`,
`T_2 = 273 + 50 = 323 K`
Therefore, ACCORDING to the gas equation, we have
`(P_1 V_1)/(T_1) = (P_2 V_2)/(t_2) " or "(750 xx 500)/288=(P_2 xx 400)/323" or "P_2 = 1051 mm`
Hence, the given gas should be compressed to 1051 mm pressure.


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