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A certain quantity of a gas occupies 300 mL when collected over water at 25^@C and 745 mm pressure. It occupied 182.6 mL in dry state at S.T.P. Find the vapour pressure of water at 25^@C.

Answer» <html><body><p><br/></p>Solution :Let us calculate the <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> <a href="https://interviewquestions.tuteehub.com/tag/exerted-7272976" style="font-weight:bold;" target="_blank" title="Click to know more about EXERTED">EXERTED</a> by 182.6 mL (at S.T.P.) of the <a href="https://interviewquestions.tuteehub.com/tag/dry-960094" style="font-weight:bold;" target="_blank" title="Click to know more about DRY">DRY</a> <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> when its volume is 300 mL and temperature is `25^@C, i.e.`, <br/> `P_1 = 760 " mm Hg. " V_1 = 182.6 mL`, <br/> `T_1 = 273 K` (at S.T.P.) <br/> `P_2 = ?, "" V_2 = 300 ml, "" T_2 = 25 + 273 = 298 K` <br/> According to the gas equation, `(P_1V_1)/T_1 = (P_2V_2)/T_2`<br/>Substituting the values, we have <br/> `(760 xx 182.6)/273 =(P_2 xx 300)/298 or P_2 = 504.9` mm Hg <br/>Under <a href="https://interviewquestions.tuteehub.com/tag/similar-1207900" style="font-weight:bold;" target="_blank" title="Click to know more about SIMILAR">SIMILAR</a> conditions, the wet gas exerts a pressure of 745 mm. <br/> `:." Vapour pressure of water at " 25^@C` <br/> `= 745 - 504.9 = 240.1 mm`</body></html>


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