1.

A certain reaction ocuurs in two steps as (I) `2SO_(2(g))+2NO_(2(g)) to 2SO_(3(g))+2NO_((g))` `(ii) 2NO_((g) ) +O_(2) (g) to 2NO_(2(g))` In the reaction ,______.A. `NO_(2)(g)` is intermediateB. `NO(g)` is intermediateC. `NO(g)` is cataystD. `O_(2)(g)` is intermediate

Answer» Correct Answer - B
Given
Step I :
`2SO_(2)(g)+2NO_(2)(g)to2SO_(3)(g)[email protected](g)`
Step II : `2NO(g)+O_(2)(g)to2NO_(2)(g)`
An intermediate formed in the reaction is not a part of overall reaction.
Net reaction : `2SO_(2)(g)+O_(2)(g)to2SO_(3)(g)`
As, No(g) formed in first elementary step is neither a reactant nor product in the net reaction. It is formed in one elmentary step and consumed in the next step. Thus NO,=(g) act as an intermediate.


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