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A certain sample of coal contain 1%of sulphur by weight. What is the weight of sulphur dioxide produced when 2'10^(6)kg of this coal isburnt? |
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Answer» `2xx10^(4)KG` `(2xx10^(6)xx1)/(100)=2xx10^(4)kg""S+O_(2)rarr SO_(2)` `32xx10^(-2)kg rarr 64xx10^(-3)kg. 2xx10^(4)kg rarr?` weight of sulphur dioxide `=(2xx10^(4)xx64xx10^(-3))/(32xx10^(-3))=4xx10^(4)kg` |
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