1.

A certain sample of cuprous sulphide is found to have composition Cu_(1.8) S, because of presence of some Cu_(2+) ions in the lattice. What is the mole % of Cu_(2+) in crystal ?

Answer»


Solution :
by law of conservation of charge
`2 XX X + (1.8 -x) xx 1 = 2`
`2x + 1.8 -x 2`
`x = 2-1.8`
`x = 0.2`
`% Cu^(2+) = (0.2)/(1.8) xx 100= 11.11%`.


Discussion

No Comment Found

Related InterviewSolutions