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A certain sample of cuprous sulphide is found to have composition Cu_(1.8) S, because of presence of some Cu_(2+) ions in the lattice. What is the mole % of Cu_(2+) in crystal ? |
Answer» by law of conservation of charge `2 XX X + (1.8 -x) xx 1 = 2` `2x + 1.8 -x 2` `x = 2-1.8` `x = 0.2` `% Cu^(2+) = (0.2)/(1.8) xx 100= 11.11%`. |
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