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A certain weak acid has K_(a), = 10^(-5). If the equilibrium constant for is its reaction with a strong base is repesented as yxx 10^(y) then find the value of y. |
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Answer» ` K= (1)/(K_b)= (K_a) /(K_w)=(10 ^(-5))/( 10^(-14))=10 ^(9) ` |
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