A certain weight of sodium Iodine and sodium chloride mixture when treated with sulphuric acid was found to give the same weight (as that of mixture) of sodium sulphate. The percentage composition of NaCl is

A certain weight of sodium Iodine and sodium chloride mixture when tre

1.	A certain weight of sodium Iodine and sodium chloride mixture when treated with sulphuric acid was found to give the same weight (as that of mixture) of sodium sulphate. The percentage composition of NaCl is
Answer» <html><body><p>`18.86`<br/>`52.23`<br/>`35.57`<br/>`71.14`</p>Solution :`2NaCl+H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)SO_(4)rarrNa_(2)SO_(4)+2HCl` <br/> `2NaI+H_(2)SO_(4)rarrNa_(2)SO_(4)+2HI` <br/> Let the wt of the mixture = 1 g <br/> `{:(2xx58.5g NaCl" gives",<a href="https://interviewquestions.tuteehub.com/tag/142g-1788148" style="font-weight:bold;" target="_blank" title="Click to know more about 142G">142G</a> Na_(2)SO_(4)),(<a href="https://interviewquestions.tuteehub.com/tag/xg-747279" style="font-weight:bold;" target="_blank" title="Click to know more about XG">XG</a> NaCl" gives",142 xg Na_(2)SO_(4)),(,117):}` <br/> <a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a> g of NaI gives 142g `Na_(2)SO_(4)` <br/> (1-x)g of NaI gives `((1-x)xx142)/(300)gNa_(2)SO_(4)` <br/> `(142x)/(117)+((1-x)xx142)/(300)=1impliesx=0.7114g` <br/> % of `NaCl=(0.7114)/(1)xx100=71.14`</body></html>