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A charged particle enters a (non-uniform) magnetic field varrying from point to point, both in magnitude and direction, with a certain initial velocity. What do you say about the final velocity of the particle when it leaves the field?

Answer» The force on the moving charged particle in magnetic field is `vecF=q(vecvxxvecB)`. So `vecF` is always perpendicular to the particle velocity `vecv`. Hence the magnitude of velocity remains unchanged, only the direction changes. Thus the particle will leave the varrying magnetic field with its initial velocity, but in a different direction.


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