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| 1. |
A charged particle enters a (non-uniform) magnetic field varrying from point to point, both in magnitude and direction, with a certain initial velocity. What do you say about the final velocity of the particle when it leaves the field? |
| Answer» The force on the moving charged particle in magnetic field is `vecF=q(vecvxxvecB)`. So `vecF` is always perpendicular to the particle velocity `vecv`. Hence the magnitude of velocity remains unchanged, only the direction changes. Thus the particle will leave the varrying magnetic field with its initial velocity, but in a different direction. | |