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A charged particle of specific charge `alpha` moves with a velocity `vecv=v_0hati` in a magnetic field `vecB=(B_0)/(sqrt2)(hatj+hatk)`. Then (specific charge=charge per unit mass)A. path of the particle is a helixB. path of the particle is circleC. distance moved by the particle in time `t=pi/(B_0alpha) is (piv_0)/(B_0 alpha)`D. velocity of the particle after time `t=pi/(B_0alpha) is ((v_0)/2hatj+(v_0)/2hatj)` |
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Answer» Correct Answer - (b,c) `vecVbotvecB` Therefore, path of the particle is a circle. In magnetic field, speed of the particle remains constant. Therefore, distance moved by particle in time `t=pi/(B_0alpha) is v_0t or (piv_0)/(B_0alpha)` Magnitude of velocity is always `v_0`, hence option (d) is incorrect. |
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