InterviewSolution
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InterviewSolution
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A chemist prepares `1.00 g` of pure `._(6)C^(11)`. This isotopes has half life of 21 min, decaying by the equation: `._(6)C^(11)`.`=>` `._(5)B^(11)`. + `._(-1)e^(0)`. a. What is the rate of disintegration per second (dps) at starts ? b. What is the activity and specific activity of `._(6)C^(11)` at start? c. How much of this isotope `(._(6)C^(11))` is left after 24 hr its preparation? |
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Answer» Applying, `-(dN)/(dt) = lambda N_(0)` `= (0.693)/(21 xx 60) xx (1 xx 6.02 xx 10^(23))/(11)` `= 3 xx 10^(19)` dps (b) Activity `= (3 xx 10^(19))/(3.7 xx 10^(10))` (1 curie `= 3.7 xx 10^(10)` dps) `= 8.108 xx 10^(8)` curie Sp. activity ` = 3 xx 10^(19) xx 10^(3) = 3 xx 10^(22)` dis/kg s = `8.108 xx 10^(11)` curie (c ) Applying, `N = N_(0) ((1)/(2))^(n) [n = (t)/(t_(1//2)) = (24 xx 60)/(21) = 68.57]` `N = 1 xx ((1)/(2))^(68.57) = 2.29 xx 10^(-21) g` |
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