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A chemist was performing an experiment to study the effect of varying voltage on the velocity and de Broglie wavelength of the electrons. In first experiment, the electron was accelerated through a potential difference of 1kV and in second experiment, it was accelerated through a potential difference of 2kV. The wavelength of de Broglie waves associated with electron is given by: lamda=(h)/(sqrt(2qVm)) where, V is the voltage through which an electron is accelerated. Putting the values of h, m and q we get: lamda=(12.3)/(sqrt(V))Ã… Q. The velocity of electron will be: |
Answer» <html><body><p>same in both<br/>1.4 times in second <a href="https://interviewquestions.tuteehub.com/tag/experiment-980358" style="font-weight:bold;" target="_blank" title="Click to know more about EXPERIMENT">EXPERIMENT</a> than in first experiment<br/>double in second experiment than in first experiment<br/>four <a href="https://interviewquestions.tuteehub.com/tag/tiems-1419779" style="font-weight:bold;" target="_blank" title="Click to know more about TIEMS">TIEMS</a> in the second <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> than in first case.</p>Answer :b</body></html> | |