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A closed current-carrying loop having a current I is having area A. Magnetic moment of this loop is defined as `vec(mu) = vec(IA)` where direction of area vector is towards the observer if current is flowing in anticlockwise direction with respect to the observer. If this loop is placed in a uniform magnetic field `vec(B)`, then torque acting on the loop is given by `vec(tau) = vec(mu) xx vec(B)`. Now answer the following questions: Let ring in the above question is having a radius R and a charge Q is uniformly distributed over it. Ring is rotated with a constant angular velocity `(omega)` as mentioned above. Torque acting on the ring due to magnetic force isA. `(QR^(2)omegaB)/(2)`B. `(piR^(2)qB)/(2omega)`C. `(qomegaR^(2)B)/(2pi)`D. None of the above

Answer» Correct Answer - A
Torque `=((q omegaR^(2))/(2))B(tau=MB)`


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