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A coloured solution known to contain two metal ions of different groups, was treated with excess cold sodium hydroxide solution. When filtered a whitish solid, slowly changing to brown, was retained on the filter paper and a colourless solution collected as the filtrate. Drop wise adition of hydrochloric acid to the filtrate produced a white precipitate which dissolved in excess acid. Treatment of the residue from the filter paper with a strong oxidiser, `PbO_(2)` and concentrated `HNO_(3)` on boiling produced a reddish-violet (purple) solution. White solid changing to brown is due to formation of:A. `Mn(OH)_(2)`B. `MgO`C. `AI(OH)_(3)`D. `MnO(OH)_(2)`

Answer» Correct Answer - D


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