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A colourless inorganic salt (A) decomposes completely at about `250^(@)C` to give only two products, (B) and (C), leaving no residue. The oxide (C) is a liquid at room temperature and neutral to moist litmus paper while the gas (B) is a neutral oxide. White phosphours burns in excess of (B) to produce a strong white dehydrating agent. Write balanced equations for the reactions involved in the above process. |
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Answer» (i) Since a colourless inorganic salt (A) on heating to `250^(@)C` decomposes to form two oxides (B) and (C) leaving no residue, therefore, compound (A) must be ammonium nitrate `(NH_(4)NO_(3))`. `underset((A))(NH_(4)NO_(3))overset(250^(@)C)tounderset((B))(N_(2)O)+underset((C))(2H_(2)O)` (ii) The fact that inorganic salt (A) is actually ammonium nitrate is confirmed by the observation that oxide (C), i.e., `H_(2)O` is a liquid at room temperature. (iii) If the oxide (C) is `H_(2)O` then other neutral oxide (B) must be nitrous oxide, `N_(2)O`. (iv) The fact that the neutral oxide (B) is actually `N_(2)O` is confirmed by the observation that white phosphorus burns in `N_(2)O` to form phosphorus pentoxide which is a strong dehydrating agent. `underset("Nitrous oxide (B)")(10N_(2)O)+P_(4)tounderset("Phosphorus pentoxide")(P_(4)O_(10))+10N_(2)` Thus, inorganic salt (A) is ammonium nitrate `(NH_(4)NO_(3))`, (B) is nitrous oxide `(N_(2)O)` and (C) is water `(H_(2)O)`. |
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