A compound (A) of boron reacts with NMe_3 to give an adduct (B) which on hydrolysis gives a compound (C) and hydrogen gas. Compound (C) is an acid. Identify the compounds A, B and C. Give the reactions involved.

A compound (A) of boron reacts with NMe_3 to give an adduct (B) which

1.	A compound (A) of boron reacts with NMe_3 to give an adduct (B) which on hydrolysis gives a compound (C) and hydrogen gas. Compound (C) is an acid. Identify the compounds A, B and C. Give the reactions involved.
Answer» Solution :Compound (A) of boron reacts with `NMe_3` and gives an adduct (B) THUS compound (A) is Lewis acid. SINCE (B) on hydrolysis gives an acid (C) and `H_2` gas, THEREFORE (A) is `B_2H_6`, [B] is an adduct `2BH_3 NMe_3` and (C) is boric acid. Reactions are as follows : `underset"Diborane (A)"(B_2H_6) + underset"Adduct (B)"(2NMe_3)to underset("Adduct (B)")(2BH_3 NMe_3)` `underset"(B)"(BH_3NMe_3) + 3H_2O to underset"Boric acid (C)"(H_3BO_3) + NMe_3 + 6H_2`