A compound AB crystallises in bcc lattice with the unit cell edge length of 380 pm. Calculate (i)The distance between oppositely charged ions in the lattice. (ii) radius ofB^(-) if he radius ofA^(+) is 190 pm.

A compound AB crystallises in bcc lattice with the unit cell edge leng

1.	A compound AB crystallises in bcc lattice with the unit cell edge length of 380 pm. Calculate (i)The distance between oppositely charged ions in the lattice. (ii) radius ofB^(-) if he radius ofA^(+) is 190 pm.
Answer» <html><body><p><br/></p>Solution :(i) For <a href="https://interviewquestions.tuteehub.com/tag/bcc-389643" style="font-weight:bold;" target="_blank" title="Click to know more about BCC">BCC</a>, <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> ` A^(+) an <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>^(-) = sqrt3/2 ` a, i.e, it is half of <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> diagonal</body></html>