1.

A compound consisting of the monvalent ions,A^(+) , B^(-)crystallizes in the body -centred cubic lattice. (i) What is the formula of the compound ?(ii)If one ofA^(+)ions from the corner is replaced by a monovalent ion C^(+). What would be the simplest formula of the resulting compound ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i) Contribution of ` A^(+)`ions present at the corners to <a href="https://interviewquestions.tuteehub.com/tag/wards-1448848" style="font-weight:bold;" target="_blank" title="Click to know more about WARDS">WARDS</a> unit cell=` 8 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>/8 =1` <br/> Contribution of `B^(-)`<a href="https://interviewquestions.tuteehub.com/tag/ion-1051153" style="font-weight:bold;" target="_blank" title="Click to know more about ION">ION</a> present at the body - centre =1 <br/> Ration of ` A^(+) : B^(-)`= 1:1 . Hence , the formula is AB. <br/> (ii)` A^(+)` ions at the corners = 7. Hence, their contribution towards unit cell = ` 7/8`<br/> ` C^(+)` ion at one corner contributes = `1/8` <br/> ` B^(-)` ion at the body centre has contribution =1 . <br/> Hence, ratio of A:B :C =` 7/8 : 1/8 :1 = 7: 1 : 8`<br/> Formula will be ` A_(7)BC_(8)`</body></html>


Discussion

No Comment Found

Related InterviewSolutions