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A compound contains 26.57% potassium, 35.36% chromium and the remaining oxygen. What is its empirical formula? (At.wt. of K=39.1, Cr=52, 0=16)

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a> of K : Cr : O = `(26.6)/(39.1) : (35.4)/(52) : (38.1)/(<a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a>) = 0.68 : 0.68 : 2.38 = 2 : 2 : 7` <br/> The empirical formula is ` K_(2)Cr_(2)O_(7)`.</body></html>


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