A compound contains 40% of Sulphur and 60% of Oxygen, what is the empirical formula of the compound?(a) SO2(b) SO3(c) SO4(d) None of the mentionedI got this question in an interview.Enquiry is from Mole Fraction and Mass(Weight) Fraction topic in division Moles, Density & Concentration of Basic Chemical Engineering

A compound contains 40% of Sulphur and 60% of Oxygen, what is the empi

1.	A compound contains 40% of Sulphur and 60% of Oxygen, what is the empirical formula of the compound?(a) SO2(b) SO3(c) SO4(d) None of the mentionedI got this question in an interview.Enquiry is from Mole Fraction and Mass(Weight) Fraction topic in division Moles, Density & Concentration of Basic Chemical Engineering
Answer» The correct OPTION is (b) SO3 The best I can explain: Mole FRACTION of Sulphur = (40/32)[(40/32) + (60/16)] = 0.25, => Mole fraction of oxygen = 0.75, => Empirical formula of compound is SO3.

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