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A compound formed by elements A and B has a cubic structure in which A atoms are at the corners of the cube and B atoms are at the face centres. Derive the formula of the compound. |
Answer» <html><body><p></p>Solution :As A atoms are <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> at the <a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> <a href="https://interviewquestions.tuteehub.com/tag/corners-934262" style="font-weight:bold;" target="_blank" title="Click to know more about CORNERS">CORNERS</a> of the cube, therefore , number of atoms of A in the unit <a href="https://interviewquestions.tuteehub.com/tag/cell-25680" style="font-weight:bold;" target="_blank" title="Click to know more about CELL">CELL</a> `=1/8xx8=1` <br/> As B atoms are present in the face centres of the 6 <a href="https://interviewquestions.tuteehub.com/tag/faces-982657" style="font-weight:bold;" target="_blank" title="Click to know more about FACES">FACES</a> of the cube, therefore, number of atoms of B in the unit cell`=1/2xx6=3` <br/> `therefore` Ratio of atoms A:B =1:3 <br/> Hence, the formula of the compound is `AB_3`</body></html> | |