A compound forms hexagonal close-packed structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids ?

A compound forms hexagonal close-packed structure. What is the total n

1.	A compound forms hexagonal close-packed structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids ?
Answer» Solution :No. of ATOMS in the CLOSE packing =0.5 mol =`0.5 xx 6.022xx10^23 =3.011xx10^23` No. of octahedral VOIDS= No. of atoms in the packing =`3.011xx10^23` No. of tetrahedral voids= 2 x No. of atoms in the packing =`2xx3.011xx10^23 =6.022xx10^23` Total no. of voids =`3.011xx10+6.022xx10^23=9.033xx10^23`