Saved Bookmarks
| 1. |
A compound has molar of 98.98g. The analysis gave 24.27%C, 4.07%H and 71.6% CI. Determine the molecular formula of alkane from which the chlorinated compound is obtained. |
|
Answer» Solution :`C : H : CI = (24.27)/(12) : (4.07)/(1) : (71.6)/(35.5) = 1 : 2 : 1 ` Empirical FORMULA is ` CH_(2)CI` NUMBER of repeating empirical units in the MOLECULAR formula `= ("Molecular formula mass" )/("Empirical formula mass")=(98.98)/(49.5) = 2` Molecular formula is `C_(2)H_(4)CI_(2)` The formula of alkane from which the halogenated compound is obtained `= C_(2)H_(6)`. |
|