A compound has molar of 98.98g. The analysis gave 24.27%C, 4.07%H and 71.6% CI. Determine the molecular formula of alkane from which the chlorinated compound is obtained.

A compound has molar of 98.98g. The analysis gave 24.27%C, 4.07%H and

1.	A compound has molar of 98.98g. The analysis gave 24.27%C, 4.07%H and 71.6% CI. Determine the molecular formula of alkane from which the chlorinated compound is obtained.
Answer» <html><body><p></p>Solution :`C : <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a> : CI = (24.27)/(12) : (4.07)/(1) : (71.<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)/(35.5) = 1 : 2 : 1 `<br/> Empirical <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> is ` CH_(2)CI` <br/> <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of repeating empirical units in the <a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> formula `= ("Molecular formula mass" )/("Empirical formula mass")=(98.98)/(49.5) = 2` <br/> Molecular formula is `C_(2)H_(4)CI_(2)` <br/> The formula of alkane from which the halogenated compound is obtained `= C_(2)H_(6)`.</body></html>