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A Compound having the empirical formula C_(6) H_(6) O has the vapour density 47 . Find its Molecular formula. |
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Answer» Solution :EMPIRICAL Formula ` = C_(6) H_(6) O` `n = ("MOLAR MASS")/("Calculated empirical formula mass")` `= (2 xx "vapour DENSITY")/(94) = (2 xx 47)/(94) = 1 ` molecular formula `(C_(6)H_(6)O) xx 1 = C_(6) H_(6) O` |
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