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A compound having the empirical formula C_(6)H_(6)O has the vapour density 47. find its Molecular formula (ii) The Simple A romatic Hydrocarbon compound (A) reacts with Bromine |
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Answer» Solution :Empirical formula ` = C_(6)H_(6)O` Empirical formula mass `=(6 xx 12)+(6 xx 1)+(16xx1)` =72 + 6+16 = 94 VAPOUR density =47 MOLECULAR mass `=2 xx ` Vapour density `= 2 xx 47` =94 Molecular formula `=n xx` Empirical formula `n = ("Molecular mass")/("Empirical formula mass ")` `n = 94 //94 rArr n = 1 ` Molecular formula`= 1xx C_(6)H_(6)O` `=C _(6)H_(6)O`
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