A compound of sodium does not give CO_(2) when heated but it gives CO_(2) when treated with dilute acids. A crystalline compound is found to have 37.1% Na and 14.52% H_(2)O. Hence, compound is

A compound of sodium does not give CO_(2) when heated but it gives CO_

1.	A compound of sodium does not give CO_(2) when heated but it gives CO_(2) when treated with dilute acids. A crystalline compound is found to have 37.1% Na and 14.52% H_(2)O. Hence, compound is
Answer» <html><body><p>`NaHCO_(3)10H_(2)O`<br/>`NaHCO_(3)5H_(2)O`<br/>`Na_(2)CO_(3)10H_(2)O`<br/>`Na_(2)CO_(3)H_(2)O`</p>Solution :`CO_(2)` is obatined only when the compound is decomposed by acid thus, it is `Na_(2)CO_(3)`. It cannot be `NaHCO_(3)` since, it given `CO_(2)` on heating. <br/> Probable compound is `Na_(2)CO_(3).xH_(2)O` <br/> `{:(,,"<a href="https://interviewquestions.tuteehub.com/tag/molar-562965" style="font-weight:bold;" target="_blank" title="Click to know more about MOLAR">MOLAR</a> <a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a>","Ratio"),(Na_(2)CO_(3),85.48,0.8064,1),(H_(2)O,14.52,0.8064,1):}` <br/> Thus, compound is `Na_(2)CO_(3)*H_(2)O` <br/> <a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> `=124" g "mol^(-1)` <br/> percentage of sodium `=(2xx23)/(124)xx100=37.1%`</body></html>