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A compound of sodium does not give CO_(2) when heated but it gives CO_(2) when treated with dilute acids. A crystalline compound is found to have 37.1% Na and 14.52% H_(2)O. Hence, compound is |
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Answer» `NaHCO_(3)*10H_(2)O` Probable compound is `Na_(2)CO_(3).xH_(2)O` `{:(,,"MOLAR RATIO","Ratio"),(Na_(2)CO_(3),85.48,0.8064,1),(H_(2)O,14.52,0.8064,1):}` Thus, compound is `Na_(2)CO_(3)*H_(2)O` MOLECULAR WEIGHT `=124" g "mol^(-1)` percentage of sodium `=(2xx23)/(124)xx100=37.1%` |
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