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A compound of the formula C_(4)H_(10)O reacts with sodium and undergoes oxidation to give a carbonyl compound which does not reduce Tollen's reagent, the original compound is |
Answer» <html><body><p>Diethyl ether<br/>n-Butyl alcohol<br/>Isobutyl alcohol<br/>sec-Butyl alcohol</p>Solution :Because the compound react with Na, it may be alcohol, phenol or a carboxylic acid. As the compound on oxidation gives a carbonyl compounds which does not reduce Tollen's reagent, the compound <a href="https://interviewquestions.tuteehub.com/tag/formed-464209" style="font-weight:bold;" target="_blank" title="Click to know more about FORMED">FORMED</a> on oxidation is a reagent, the compound is a ketone. Because only <a href="https://interviewquestions.tuteehub.com/tag/secondary-638692" style="font-weight:bold;" target="_blank" title="Click to know more about SECONDARY">SECONDARY</a> `(2^(@))` alcohols on oxidation yield <a href="https://interviewquestions.tuteehub.com/tag/ketones-1063498" style="font-weight:bold;" target="_blank" title="Click to know more about KETONES">KETONES</a>, thethe original compound is a secondary alcohol. <br/> `underset(2^(@)-"Butyl alcohol (D)")(CH_(3)-overset(OH)overset(|)(<a href="https://interviewquestions.tuteehub.com/tag/ch-913588" style="font-weight:bold;" target="_blank" title="Click to know more about CH">CH</a>)-CH_(2)-CH_(3))overset([O])rarrunderset("Butane-2-one")(CH_(3)-overset(O)overset(||)(CH)-CH_(2)-CH_(3))`</body></html> | |