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A compound which contains one atom of X and two atoms of Y for each three atoms of Z is made by mixing 5.00 g of X, 1.15 xx 10^(23) atoms of Y and 0.03 mole of Z atoms. Given that only 4.40 g of the compound is formed. Calculate the atomic weight of Y if the atomic weights of X and Z are 60 and 80 amu respectively.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Moles of <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> =`(5)/(60)= 0.08` mole <br/> Moles of Y = `(1.15xx10^(23))/(6.022xx10^(23))=0.19` mole <br/> Moles of Z = 0.03 mole . <br/> Since the formula of the compound is `XY_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)Z_(3)` <br/>moles of X : moles of Y : moles of Z =1 : 2:3 = 0.01 : 0.02: 0.03 . Comparing these values with the moles of X, Y and Z calculated above, we find that moles of X and Y are in excess and therefore, moles of X and Y associated with 0.03 mole of Z are 0.01 and 0.02 mole respectively. Now, <br/> <a href="https://interviewquestions.tuteehub.com/tag/wt-1462289" style="font-weight:bold;" target="_blank" title="Click to know more about WT">WT</a> of Z + wt . of Y + wt. of Z = wt. of `XY_(2)Z_(3)` <br/> or `0.01xx60 +0.02 xx ` at. wt. of Y + `0.03xx80 = 4.4 ` <br/> `:. ` at .wt. of Y = 70 <a href="https://interviewquestions.tuteehub.com/tag/amu-25369" style="font-weight:bold;" target="_blank" title="Click to know more about AMU">AMU</a> .</body></html>


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