A compound with molecular formula C_(4)H_(10)O_(4) on acylation with acetic anhydride gives a compound with molecular formula C_(12)H_(18)O_(8). How many hydroxyl groups are present in the compound?

A compound with molecular formula C_(4)H_(10)O_(4) on acylation with a

1.	A compound with molecular formula C_(4)H_(10)O_(4) on acylation with acetic anhydride gives a compound with molecular formula C_(12)H_(18)O_(8). How many hydroxyl groups are present in the compound?
Answer» <html><body><p>1<br/>2<br/>3<br/>4</p>Solution :Mol. Mass of `C_(4)H_(10)O_(4)` <br/> `= 12 xx 4 + 10 xx 1 + 4 xx 16 = 122` <br/> Mol. Mass of acylated product `(C_(12)H_(18)O_(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>))` <br/> `= 12 xx 12 + 18 xx 1 + 4 xx 16 = <a href="https://interviewquestions.tuteehub.com/tag/290-1834725" style="font-weight:bold;" target="_blank" title="Click to know more about 290">290</a>` <br/> Increase in mol. Mass `= 290 - 122 = 168` <br/> The reaction involved is `-OH + CH_(3)COCl rarr - O.CO. CH_(3) + <a href="https://interviewquestions.tuteehub.com/tag/hcl-479502" style="font-weight:bold;" target="_blank" title="Click to know more about HCL">HCL</a>` <br/> Increase in mol mass due to one `-OH` group = (Mol. mass of `COCH_(3)`) - At. mass of H `= 2 xx 12 + 16 + 3 - 1 = 42` <br/> `:.` No. of `-OH` groups `= (168)/(42) = 4`</body></html>