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A compound X declourises Br_(2) water and reacts slowly with conc H_(2)SO_(4) to give an addition product. X reacts with HBr to form Y. Y reacts with NaOH to form Z. on oxidation Z gives hexan-3-one. X, Y and Z in the reactions are underset("Addition product") underset(darr "conc. "H_(2)SO_(4))(X) overset(Br_(2)" water")to"Decolourisation" X overset(HBr) to Y overset(NaOH) to Z overset([O])to CH_(3)CH_(2)underset("Hexan-3-one")(CH_(2)-underset(O)underset(||)(C)-CH_(2)CH_(3))

Answer» <html><body><p>`X=CH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)CH_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)CH=CHCH_(3),Y=CH_(3)CH_(2)CH(Br)CH(Br)CH_(2)CH_(3),Z=CH_(3)CH_(2)CH_(3)`<br/>`X=CH_(3)CH=CHCH_(3),Y=CH_(3)CH(Br)CH(Br)CH_(3),Z=CH_(3)CH_(2)CH_(2)OH`<br/>`X=CH_(3)CH_(2)CH=CHCH_(2)CH_(3),Y=CH_(3)CH_(2)-<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>(Br)underset(|)(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>)H-CH_(2)CH_(2)CH_(3),Z=CH_(3)CH_(2)CH_(2)-underset(OH)underset(|)(C)H-CH_(2)CH_(3)`<br/>`X=CH_(3)CH_(2)CH_(2)CH=CHCH_(3),Y=CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)CH_(2)Br, Z=CH_(3)CH_(2)CH_(2)CH_(2)OH`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_OBJ_FING_CHE_XI_C13_E01_053_S01.png" width="80%"/></body></html>


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