1.

A compound X declourises Br_(2) water and reacts slowly with conc H_(2)SO_(4) to give an addition product. X reacts with HBr to form Y. Y reacts with NaOH to form Z. on oxidation Z gives hexan-3-one. X, Y and Z in the reactions are underset("Addition product") underset(darr "conc. "H_(2)SO_(4))(X) overset(Br_(2)" water")to"Decolourisation" X overset(HBr) to Y overset(NaOH) to Z overset([O])to CH_(3)CH_(2)underset("Hexan-3-one")(CH_(2)-underset(O)underset(||)(C)-CH_(2)CH_(3))

Answer»

`X=CH_(3)CH_(2)CH=CHCH_(3),Y=CH_(3)CH_(2)CH(Br)CH(Br)CH_(2)CH_(3),Z=CH_(3)CH_(2)CH_(3)`
`X=CH_(3)CH=CHCH_(3),Y=CH_(3)CH(Br)CH(Br)CH_(3),Z=CH_(3)CH_(2)CH_(2)OH`
`X=CH_(3)CH_(2)CH=CHCH_(2)CH_(3),Y=CH_(3)CH_(2)-UNDERSET(Br)underset(|)(C)H-CH_(2)CH_(2)CH_(3),Z=CH_(3)CH_(2)CH_(2)-underset(OH)underset(|)(C)H-CH_(2)CH_(3)`
`X=CH_(3)CH_(2)CH_(2)CH=CHCH_(3),Y=CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)CH_(2)Br, Z=CH_(3)CH_(2)CH_(2)CH_(2)OH`

SOLUTION :


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