A compound X, of boron reacts with NH_3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF_3 with lithium aluminum hydride. The compounds X and Y are represented by the formulas…

A compound X, of boron reacts with NH_3 on heating to give another com

1.	A compound X, of boron reacts with NH_3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF_3 with lithium aluminum hydride. The compounds X and Y are represented by the formulas…
Answer» `B_2H_6, B_3N_3H_6` `B_2O_3 , B_3N_3H_6` `BF_3, B_3N_3H_6` `B_3N_3H_6, B_2H_6` Solution :(i)`B_2H_6` reacts with ammonia and gives `B_2H_6 . 2NH_3`which is formulated as `[BH_2(NH_3)_2]^(+) [BH_4]^(-)`and on HEATING gives `B_3H_3H_6`borazine ALSO called borazole. `underset"(X)"(3B_2H_6+6NH_3) to 3[BH_2(NH_3)_2]^(+) [BH_4]^(-) oversetDeltato underset"(Y)"(2B_3N_3H_6) + 12H_2` (ii)`B_2H_6` can be prepared by reduction of `BF_3` with `LiAlH_4 . 4BF_3 + 3LiAlH_4 to underset"(Y)"(2B_2H_6) + 3LiF + 3AlF_3`