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A container has H2 at 27^oC and molar volume 1 liter/mole, if a = 9.24 atm(liter/mole), b = 0.0907 liter/mole, what is the temperature of H2? (Use vander waal equation)(a) 7.5 atm(b) 12.4 atm(c) 15.6 atm(d) 17.8 atmThe question was asked by my school teacher while I was bunking the class.My question is based upon Equations of State in section Real Gases: Equations of State, Single Component Two Phase Systems, Saturation & Condensation of Basic Chemical Engineering

Answer»

Correct option is (d) 17.8 atm

Easiest EXPLANATION: (p + a/V^2)(V – b) = RT, => p = 0.0821*300/(1 – 0.0907) – 9.24/1^2 = 17.8 atm.



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