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A container has O2 at 5 atm and molar volume 2 liter/mole, if a = 9.24 atm(liter/mole), b = 0.0907 liter/mole, what is the temperature of O2? (Use vander waal equation)(a) 140 K(b) 150 K(c) 170 K(d) 190 KI had been asked this question in examination.The doubt is from Equations of State topic in section Real Gases: Equations of State, Single Component Two Phase Systems, Saturation & Condensation of Basic Chemical Engineering

Answer»

Right answer is (c) 170 K

To EXPLAIN I would SAY: (p + a/V^2)(V – b) = RT, => T = (5 + 9.24/2^2)(2 – 0.0907)/0.0821 = 170 K.



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